Category Archives: address

An array AR[-4…6, -2 … 12] stores elements in Row Major wise, with the address AR[2][3] as 4142. If each element requires 2 bytes of storage. Find the Base address Given i =2, j=3, W= 2 bytes B=? AR[-4 …6, … Continue reading →

A square matrix M[][] of size 10 is stored in the memory with each element requiring 4 bytes of storage. If the base address is M[0][0] is 1840, determine the address at M[4][8] when the matrix is stored in Row … Continue reading →

A matrix B[10][7] is stored in the memory with each requiring 2 bytes of storage. If the base address at B[x][1] is 1012 and the address at B[7][3] is 1060 determine the value of ‘x’ where the matrix is stored … Continue reading →

A square matrix A[mxm] is stored in the memory with each element requiring 2 bytes of storage. If the base addressA[1][1] is 1098 and the address at A[4][5] is 1144, determine the order of the matrix A[mxm] when the matrix … Continue reading →

A matrix ARR[ – 4…6, 3….8] is stored in the memory with each element requiring 4 bytes of storage. If the base address is 1430, find the address of ARR[3][6] when the matrix is stored in Row Major Wise. Row … Continue reading →

A matrix A[m][m] is stored in the memory with each element requiring 4 bytes of storage. If the base address at A [1][1] is 1500 and address of A [4][5] is 1608, determine the order of matrix when it is … Continue reading →

A matrix P[15][10] is stored with each element requiring 8 bytes of storage. If the base address at P[0][0] is 1400, determine the address at P[10][7] when the matrix is stored in Row Major Wise. Row Major Wise: P[i][j] = … Continue reading →

A matrix A[m][n] is stored with each element requiring 4 bytes of storage. If the base address at A[1][1] is 1500 and the address at A[4][5] is 1608, determine the number of rows of the matrix when the matrix is … Continue reading →

The array D[-2…10][3…8] contains double type elements. If the base address is 4110, find the address of D[4][5], when the array is stored in Column Major Wise. The given values are:B = 4110, W = 8 bytes or 64 bits … Continue reading →