A matrix P[15][10] is stored with each element requiring 8 bytes of storage. If the base address at P[0][0] is 1400, determine the address at P[10][7] when the matrix is stored in Row Major Wise.
Row Major Wise: P[i][j] = BA + W [ (i – lr )* column + (j – lc]
= 1400 + 8[ (10-0)*10 + (7-0)]
= 1400 + 856
P[10][7] = 2256